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10^10 doesn't work!!!

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xspider

Very Active Member

Group: Members
Posts: 64
Member No.: 10609
Joined: 27-July 08

he all yeah i'm here x) i just don't know why 10^10 doesn't give me the right result

CODE

#include <stdio.h>
#include <math.h>
int main()
{
int x = 1,p1;
while ( x < 11 ) {
p1=pow(x,x);
printf( "%d^%d=%d\n", x,x,p1 );
x++;
}
getchar();
}

and also i wan't to do an addition to the results like that:
1^1+2^2+3^3+4^4+5^5+6^6+7^7+8^8+9^9+10^10=10405071317

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shoorick
Extremely Active Member Group: Admins Posts: 2314 Member No.: 160 Joined: 22-June 04	it is possible 10^10 does not fit into int... 04 294 967 295 - max for 32 bit uint (signed int - twice less) 10 405 071 317 - your value maybe, overflow error should rise in this case, but who knows why not 8)

xspider

Very Active Member

Group: Members
Posts: 64
Member No.: 10609
Joined: 27-July 08

so should i use something else except int

damn i liked it x) anyway i've used double with format #f and look what it gave me

CODE

1^1=1.000000
2^2=4.000000
3^3=27.000000
4^4=256.000000
5^5=3125.000000
6^6=46656.000000
7^7=823543.000000
8^8=16777216.000000
9^9=387420480.000000
10^10=10000000000.000000

you can see that i gave me what i wan't but the zero's are annoying


dila
New Member Group: Members Posts: 16 Member No.: 823 Joined: 3-December 04	Use "%.0f" instead of "%g" to hide the decimal places. Also, you can use "%.3f" to display just 3 decimal places .etc

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